Find the equation of the circle centered at (3,-4) and radius =5?

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Answer 1 · 2018-06-21T09:08:03

#(x-3)^2+(y+4)^2=25#

The equation of a circle can be written as

#(x-x_0)^2+(y-y_0)^2=r^2#

Where #(x_0,y_0)# is the center, and #r# is the radius.

In this case you have all the information you need, so you just need to plug the values: given #(x_0,y_0)=(3,-4)# and #r=5# you have

#(x-3)^2+(y+4)^2=25#

Answer 2 · 2018-06-21T09:10:48

#color(green)(" Equation of the circle is " (x - 3)^2 + (y + 4)^2 = 5^2#

#"Equation of a circle " (x - h)^2 + (y-k)^2 = r^2#

#"Given : " h = 3, k = -4, r = 5#

#:. color(green)(" Equation of the circle is " (x - 3)^2 + (y + 4)^2 = 5^2#