How do you solve and graph #5h+ -4>=6# and #7h+11<32#?

1 Answer
KillerBunny
Jun 21, 2018

Let's solve each inequality for #h#:

First inequality:
#5h+(-4)\ge 6#

#therefore 5h-4 \ge 6#

#therefore 5h \ge 10#

#therefore h \ge 2#

Second inequality:
#7h+11<32#

#therefore 7h < 21#

#therefore h < 3#

So, we are looking for all numbers that are more that #2# (included) but smaller than #3# (excluded).

To graph this on a number line, you can highlight the parte between #2# and #3#, pointing out in some way that #2# belongs to your set, while #3# doesnt.

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