How do you simplify $\frac{9}{\sqrt{6} - \sqrt{5}}$ $9/(sqrt6 - sqrt5)$ ?

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How do you simplify $\frac{9}{\sqrt{6} - \sqrt{5}}$ $9/(sqrt6 - sqrt5)$ ?

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Answer 1 · 2018-06-16T01:29:17

This problem can be solved by using using the conjugate of the denominator and rationalization

Explanation:

$\frac{9}{\sqrt{6} - \sqrt{5}}$ $\frac{9}{\sqrt{6}-\sqrt{5}}$

$= \frac{9}{\sqrt{6} - \sqrt{5}} \cdot \frac{\sqrt{6} + \sqrt{5}}{\sqrt{6} + \sqrt{5}}$ $=frac{9}{\sqrt{6}-\sqrt{5}} * frac{\sqrt{6}+\sqrt{5}}{\sqrt{6}+\sqrt{5}}$

$= \frac{9 \cdot (\sqrt{6} + \sqrt{5})}{{(\sqrt{6})}^{2} - {(\sqrt{5})}^{2}}$ $=frac{9*(\sqrt{6}+\sqrt{5})}{(\sqrt{6})^2-(\sqrt{5})^2}$

$= \frac{9 \cdot (\sqrt{6} + \sqrt{5})}{6 - 5} = 9 \cdot (\sqrt{6} + \sqrt{5})$ $=frac{9*(\sqrt{6}+\sqrt{5})}{6-5}=9*(\sqrt{6}+\sqrt{5})$

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How do you simplify $\frac{9}{\sqrt{6} - \sqrt{5}}$ $9/(sqrt6 - sqrt5)$ ?

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Explanation:

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