How do you solve # 1/3x+3/10=13/90#?

1 Answer
MeneerNask
Jun 15, 2018

My first step would be to multiply everything by #90# to get rid of the fractions.

Explanation:

#->90/3x+(9cancel0*3)/(1cancel0)=(cancel90*13)/cancel90->30x+27=13#

Subtract #27# from both sides:
#->30x+cancel27-cancel27=13-27->30x=-14#

Now divide by #30#:
#->x=-14/30=-7/15#

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