How do you solve #-4j + 14= - 2( 2j - 7)#?

Question

1410 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-06-14T16:52:58

#j=0#

This requires a lot of moving around and negative knowledge.

#-4j+14=-2(2j-7)#

First, we must expand the brackets:

#-2(2j-7) = -4j^2+14#

Then we can move on to changing the numbers around (remember to change the signs:

#-4j+14=-4j^2+14#

#-4j+4j^2=-14+14#

And then simplify from there:

#j=0#

Hope this helped.