How many moles of NaCl will react completely with 18.5 L F2 gas at 300.0 K and 1.00 atm? 0.751 mol NaCl 1.33 mol NaCl 1.50 mol NaCl 2.66 mol NaCl

1 Answer
zhirou
Jun 13, 2018

#1.50# moles of #NaCl#.

Explanation:

This is our balanced single-substitution reaction:

#2NaCl + F_2 -> 2NaF + Cl_2#

From this, we can see that #1# mole of #F_2# gas corresponds to #2# moles of #NaCl#.

To calculate the moles of #NaCl# needed to react with #F_2# gas, we'll first need to find the number of moles of #F_2#.
This can be done using the Ideal Gas Law:

#pV = nRT#

Where #p# is pressure, #V# is volume, #n# is number of moles, #R# is the gas constant, and #T# is temperature.

We're already given volume, temperature, and pressure from the question, so we can just plug those values in and solve for #n#:

#pV = nRT#

#n = (pV)/(RT) = ("1.00 atm" xx "18.5 L")/("0.08206 L atm/K mol" xx "300.0 K") = "0.751 mol"#

Since #1# mole of #F_2# gas corresponds to #2# moles of #NaCl#, #"0.751"# moles of #F_2# gas will correspond to #2xx0.751 = 1.50# moles of #NaCl#.

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