How do you factor #y= x^2 – 5x – 6 # ?

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Answer 1 · 2018-06-11T14:21:09

#(x+1)(x-6)#

using the formula

#(-b+- sqrt(b^2-4xxaxxc))/(2xxa)#

with #a=1, b=-5, c=-6#

gives the factors

#(5+-sqrt(25+24))/2#

or

#(5+-7)/2

resulting in the factors #-1# and #6#