6x-9/x-5?

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Answer 1 · 2018-06-11T14:06:56

#x1= -0.88#

#x2=1.71#

Starting with #6x-9/x-5=0#,
multiplying both sides of the equation with #x#, and reordering the terms gives the equation to solve as:

#6x^2-5x-9=0#

factoring (with #a=6, b=-5, c=-9#) gives the following solutions for x:

#x= (5+-sqrt((-5)^2-4xx6xx(-9)))/(2xx6)#

#x1= -0.88#

#x2=1.71#