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How do you solve (2senx+1)(2cosx+3)=0 ?

1 Answer

Jun 10, 2018

Please see below.

Explanation:

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#(2sinx+1)(2cosx+3)=0#

#2sinx+1=0, :. sinx=-1/2, x=+-2kpi+(7pi)/6, +-2kpi+(11pi)/6#

#2cosx+3=0, :. cosx=-3/2#, this is not valid because #cosx# values are between #+1# and #-1#.

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