A 70 kg person climbs up 2 meters in 2.8 seconds. How much energy did they gain? How much power did they use?

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A 70 kg person climbs up 2 meters in 2.8 seconds. How much energy did they gain? How much power did they use?

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Answer 1 · 2018-06-09T10:00:04

1372 J ; 490 W

Explanation:

potential energy
#E= m xx g xx h = 70 kg xx 9,8 m/s^2 xx 2 m= 1372 J#
Power is the work done (= the energy gained) in an unit of time
#P= E/t= (1372J)/ (2.8 s)= 490 W#

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A 70 kg person climbs up 2 meters in 2.8 seconds. How much energy did they gain? How much power did they use?

1 Answer

Explanation:

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