How do you solve the system of equations #3x + 2y = 2# and #x = 2y - 10#?

1 Answer
Andrew D.
Jun 8, 2018

Via Substitution

Explanation:

Input #2y-10# into the first equation wherever you see #x#

So, #3(2y-10)+2y=2#

Now you can solve for #y# the same way you would solve for #x# in this equation. (Isolate the variable and simplify until you get #y=c# where #c# is a constant [number])

then, once you've solved for #y# replace #y# with your number #c# into either equation, but solve for #x# this time.

If #y=c=-4# for example, I would solve for #x# like this

#x=2(-4)-10#
#x=-8-10#
#x=-18#
Then, I'd answer the system of equations with
#y=-4# and #x=-18#

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