A Child drops a ball from a height of 10m its velocity increases at the rate of 10 M/s^2.find ? A)The velocity with which the ball strikes the ground. B)Time taken by the ball to reach the ground.

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Answer 1 · 2018-06-08T13:33:45

$v=10sqrt2$ $ms^-1$
$t=sqrt2$ sec

If the ball is dropped gently, we consider initial velocity to be 0.
$color (green)(u=0$

We have equations of motion which are valid here because of constant acceleration.

$color (blue)(2as=v^2-u^2)$

Just putting values as in your case

$2*10*10=v^2-0^2$

$200=v^2$

$color(indigo)(10sqrt2=v$

Now using $v=u+at$

$10sqrt2=0+10t$

$t=sqrt2$ sec

Answer 2 · 2018-06-08T13:35:21

I tried this:

Have a look:
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