How do you solve the system of equations:y=4, 3/5x+y=8?

When getting rid of the fraction, do you do this:
3/5x+y=8
5 5
3x+y=40

or:
3x+5y=40?

1 Answer
jk.13
Jun 7, 2018

#(x,y) = (20/3, 4)#

Explanation:

First, to answer your equation, multiplying the whole equation ("getting rid of the fraction" #3/5x+y=8# by 5 would give you #3x+5y=40#

Now, for solving the system of equations:
#3x+5y=40#
#y=4#
Those are our two equations.
We can plug #y=4# (which is given) into the other equation to solve for x.
#3x+5(4)=40#
#3x+20=40#
#3x=20#
#x=20/3#
Because the y-value was given to us, we can conclude that #(x,y) = (20/3, 4)#

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