Given #log_3(5x^2+x−y)=1# then #y=ax^n+x+b#, what is #a#, #b#, #n#?

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Answer 1 · 2018-06-07T07:48:43

#a=5#
#n=2#
#b=-3#

Using the rule of logs, #log_a(a)=1#, we know that #5x^2+x-y=3#

#y=5x^2+x-3#

#a=5#
#n=2#
#b=-3#

Answer 2 · 2018-06-07T07:49:12

See explanatio.

#log_3(5x^2+x-y)=1#

So we can write that: