What value of #x# in the interval #0°<=x<=180°# satisfies the equation #sqrt3 tanx+1=0#?

1 Answer
Anjali G
Jun 6, 2018

#x = 150^("o")#

Explanation:

#sqrt3 tan x + 1 = 0#

#sqrt3 tan x = -1#

#tan x = frac{-1}{sqrt3}#

Within the quadrants I and II of the unit circle, the only quadrant for which #tan x# would be negative is quadrant 2.
Wikipedia

From looking at the unit circle, we can see that the ratio of #sinx# to #cosx# in quadrant II is #frac{(1/2)}{((-sqrt3 )/ 2)}# when #x# is #150^("o")#

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