2AL #(s)# + 6HCL#3(aq)# #rarr# 2AlCl#3(aq)# + 3H#2(g)# 0.040 mol piece of aluminium reacted completely in 20s. the rate of formation of hydrogen gas is?
2AL #(s)# + 6HCL#3(aq)# #rarr# 2AlCl#3(aq)# + 3H#2(g)#
2AL
1 Answer
Jun 6, 2018
Explanation:
From the equation, we can see that the ratio of number of moles:
Al : HCl : AlCl3 : H2 (Assuming that HCl3 was a typo)
is equal to:
2 : 6 : 2 : 3 (As the numbers in front of each substances show)
Therefore, if 0.040 mol of aluminium reacted completely, than
Thus,
Hope that makes sense!