How do you solve #3+ y \geq 2.4#?

2 Answers
Jacobi J.
Jun 6, 2018

#y>=-0.6#

Explanation:

The key realization is that we want to undo any operation being applied to #y#. Right now, it is only being added to some value, so we want to subtract that value to solve for it.

Let's subtract #3# from both sides. We get

#y>=-0.6#

Hope this helps!

seol
Jun 6, 2018

#y\ge-1.6#

Explanation:

#\color(blue)(3)+y\ge\color(blue)(2.4)#
Combine like terms by isolating variable.

#\cancel(\color(blue)(3)\color(skyblue)(-3))+y\ge\color(blue)(2.4)\color(skyblue)(-3)#
#y\ge2.4-3\rArr-1.6#
#\thereforey\ge-1.6#

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