How to find net capacitance?

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1 Answer
Ananda Dasgupta
Jun 6, 2018

#4\ mu"F"#

Explanation:

The two #2\ mu"F"# capacitors are in parallel, so they can be replaced by their equivalent capacitance of #4\ mu"F"#.

This leaves us with two parallel branches, each having two #4\ mu"F"# capacitors in series.

The capacitance of each branch is #(4\ mu"F"times 4\ mu"F")/(4\ mu"F"+4\ mu"F") = 2\ mu"F"#.

So, finally we have two #2\ mu"F"# capacitors in parallel, leading to an overall equivalent capacitance of #4\ mu"F"#

Note
For two capacitors #C_1# and #C_2# in series, the equivalent capacitance is #(C_1C_2)/(C_1+C_2)#, while the equivalent of parallel capacitors is #C_1+C_2#

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