Solve for x?

Question

If $y = a {log}_{10} x$ $y = a log_10 x$ , find x when a = 2 and y = 3

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Answer 1 · 2018-06-05T13:56:56

I tried this:

Let us rearrange it and use our values:

${log}_{10} x = \frac{y}{a}$ $log_(10)x=y/a$

${log}_{10} x = \frac{3}{2}$ $log_(10)x=3/2$

use the definition of log:

$x = 10^{\frac{3}{2}}$ $x=10^(3/2)$

use the property of exponents:

$x = \sqrt{10^{3}}$ $x=sqrt(10^3)$

giving:

$x = 10 \sqrt{10} = 31.62$ $x=10sqrt(10)=31.62$

Answer 2 · 2018-06-05T14:09:46

$x \approx 31.622777$ $x approx 31.622777$

$3 = 2 {log}_{10} x$ $3 = 2log_10 x$

${log}_{10} x = \frac{3}{2}$ $log_10 x= 3/2$

$x = 10^{\frac{3}{2}}$ $x= 10 ^(3/2)$

$x \approx 31.622777$ $x approx 31.622777$