How do you prove #sin(x+y)# = #(tanx+tany)/(secxsecy)# ?

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How do you prove #sin(x+y)# = #(tanx+tany)/(secxsecy)# ?

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Answer 1 · 2018-06-05T00:50:02

See below

Explanation:

#sin(x+y) = sin x cos y+cos x sin y#
#qquad = cos x cos y (sin x/cos x+sin y/cosy)#
#qquad = 1/sec x 1/sec y(tanx+tan y)#
#qquad = (tan x+tan y)/(sec x sec y)#

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How do you prove #sin(x+y)# = #(tanx+tany)/(secxsecy)# ?

1 Answer

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