Can someone help me solve this trigonometric equation problem step by step? Thank You!

Question

Solve the equation within [0,2π][0,2π]. Write your solutions separated with commas. If no solutions exist, write no solution.

6sin(x−2)=14

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Answer 1 · 2018-06-03T01:45:10

This question #6sin(x-2) = 14# is wrong. Hence No Solution

Since, The value of #sinx# can only lie between [1,-1] for any value of #x in RR#.
i.e #-1<=sinx<=1# for every #x in RR#

so in the equation

#6sin(x-2) = 14#

#rArr sin(x-2) = 2.33 #

and #2.33>1#

Therefore the question is wrong since the value of the #sin# can never be #2.33#.