how to find all values of x for which the tangent to y=x-(1/x) is parallel to the line 2x-y=5?

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Answer 1 · 2018-06-01T10:02:24

#x=+-1#

Given curve is-
#y= x-1/x#

#dy/dx= 1+1/x^2#

#Slope= 1+1/x^2#

Slope of the line #2x-y=5# is #2#

By giving condition,

#2= 1+1/x^2#

#1= 1/x^2#

#1=x^2#

#x=+-1#