3x+5=-16 how do you solve ?

Question

2032 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-31T20:24:34

Solving for x gives us $- 7$ $-7$

To solve for $x$ $x$ , you need to subtract 5 from both sides which gives us

$3 x = - 21$ $3x=-21$

Then you divide both sides by $3$ $3$ which gives us $x = - 7$ $x=-7$

But, you should double check to see if $- 7$ $-7$ works in when plugging it into the equation or otherwise you did something wrong.

$3 (- 7) + 5 = - 16$ $3(-7)+5=-16$

$- 21 + 5 = - 16$ $-21+5=-16$

Distributed the $- 7$ $-7$ to the $3$ $3$ then added $- 21$ $-21$ to $5$ $5$

Answer 2 · 2018-05-31T20:42:31

$x = - 7$ $x = -7$

$3 x + 5 = - 16$ $3x + 5 = -16$

Subtracting $5$ $5$ from both sides;

$3 x + 5 - 5 = - 16 - 5$ $3x + 5 - 5 =-16 -5$

$3 x + 0 = - 16 - 5$ $3x + 0= -16 -5$

$3 x = - 21$ $3x = -21$

Dividing both sides by the coefficient of $x$ $x$

$\frac{3 x}{3} = \frac{- 21}{3}$ $(3x)/3 = (-21)/3$

$(cancel3x)/cancel3 = (-21)/3$

$x = (-21)/3$

$x = -7$