Sin(-2π/3)?

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Answer 1 · 2018-05-30T08:51:36

#-sqrt3/2#

#color(blue)(sin(-(2pi)/3)#

Lets convert it into degrees,
Note:(#pi=180^circ#)

#rarrsin(-(2*180)/3)#

#rarrsin(-(2*cancel180^60)/cancel3^1)#

#rarrsin(-120^circ)#

Now, remember that #color(brown)(sin(-x)=-sin(x)#

So,

#rarrsin(-120^circ)=-sin(120^circ)#

Now lets check out the sin value of #120^circ#

paint

So, #sin(120^circ)=sqrt3/2#

So,

#color(green)(rArrsin(-(2pi)/3)=-sqrt3/2#

Hope that helps!...#phi#