How do you convert #z=5 + 12i # to polar form?

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How do you convert #z=5 + 12i # to polar form?

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Answer 1 · 2018-05-28T11:10:04

#Z=13e^(i67.38^o)#

Explanation:

Polar form is represented by #Z=|quadZ|e^(itheta)#
First find modulus #|quadZ| =sqrt(5^2+12^2)=13#
and # theta = arctan(y/x) = arctan(12/5) = 67.38^o#
So answer is #Z=13e^(i67.38^o)#

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How do you convert #z=5 + 12i # to polar form?

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