Find the partial sum?
#sum_(n=-2)^1(n+6)#
1 Answer
May 28, 2018
# sum_(n=-2)^1(n+6) = 22 #
Explanation:
We seek:
# S = sum_(n=-2)^1(n+6) #
If we expand the summation this becomes:
# S = (-2+6) + (-1+6) + (0+6) + (1+6)#
# \ \ = 4 + 5 + 6 + 7 #
# \ \ = 22 #
