How do you subtract $(3x ^ { 2} - 2x + 3) - ( x ^ { 2} - 3x + 4)$ ?

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Answer 1 · 2018-05-27T11:13:22

$2x^2+x-1$

$3x^2-2x+3-(x^2-3x+4)=3x^2-2x+3-x^2+3x-4=2x^2+x-1$

Answer 2 · 2018-05-27T11:16:48

Simplifying the above expression gives us $2x^2+x-1$

Before we start simplifying the expression, we need to distribute the negative sign on the right side which gives us $-x^2+3x-4$

So the expression we have left to simplify it further down is

$3x^2-2x+3-x^2+3x-4$

So we are combining like term but remember, we always rearrange the term from highest degree to lowest degree in standard form of an expression.

So simplifying the expression gives us:

$2x^2+x-1$

How do you subtract (3x ^ { 2} - 2x + 3) - ( x ^ { 2} - 3x + 4)(3x ^ { 2} - 2x + 3) - ( x ^ { 2} - 3x + 4)?