The chess club members bought 6 tickets to a tournament for $15. How much would they have paid if all 9 members wanted to go?

1 Answer
Qinglong Diep
May 26, 2018

For nine members, it would cost #22.50#

Explanation:

So we would set it up as a proportion to solve for x like this:

#"6 tickets"/"$15"# = #"9 tickets"/x#

So "tickets" refer to people. So since they brought 6 tickets for 6 people for 15 dollars, we need to cross multiply to see what we would get for #x#.

#15*9=135# then #135/6=22.25#

So for 9 members (or tickets), it would cost 22.50

Related questions
Impact of this question
5426 views around the world
You can reuse this answer
Creative Commons License