How do you simplify #(7-2i)(6-4i)#? Precalculus Complex Numbers in Trigonometric Form Multiplication of Complex Numbers 1 Answer Monzur R. May 26, 2018 #34-40i# Explanation: We define the product of two complex numbers #a+bi# and #c+di# as #(a+bi)(c+di):=(ac-bd)+(ad+bc)i# So #(7-2i)(6-4i)=(42-8)+(-28-12)i=34-40i# Answer link Related questions How do I multiply complex numbers? How do I multiply complex numbers in polar form? What is the formula for multiplying complex numbers in trigonometric form? How do I use the modulus and argument to square #(1+i)#? What is the geometric interpretation of multiplying two complex numbers? What is the product of #3+2i# and #1+7i#? How do I use DeMoivre's theorem to solve #z^3-1=0#? How do I find the product of two imaginary numbers? How do you simplify #(2+4i)(2-4i)#? How do you multiply #(-2-8i)(6+7i)#? See all questions in Multiplication of Complex Numbers Impact of this question 3069 views around the world You can reuse this answer Creative Commons License