How do you solve $-3< - \frac { 1} { 2} - \frac { 2x } { 3} \leq \frac { 5} { 6}$ ?

Question

1334 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-26T12:30:52

$-2<=x<3 3/4$

Multiply all by 6:
$-3*6<(-1*6)/2-(2x*6)/3<=(5*6)/6$
$-18<-3-4x<=5$

Add 3 to all:
$-15<-4x<=8$

Multiply all by -1:
$15>4x>=-8$
$-8<=4x<15$

Divide all by 4:
$-2<=x<15/4$
$-2<=x<3 3/4$

How do you solve -3< - \frac { 1} { 2} - \frac { 2x } { 3} \leq \frac { 5} { 6}-3< - \frac { 1} { 2} - \frac { 2x } { 3} \leq \frac { 5} { 6}?