How to factorize #14x^6 - 45x^3y^3 - 14y^6#?

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#14x^6 - 45x^3y^3 - 14y^6#

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Answer 1 · 2018-05-26T09:19:54

#(2x^3-7y^3)(7x^3+2y^3)#

By using substitution...

#a=x^3 and b=y^3#

#14x^6 - 45x^3y^3 - 14y^6=#
#14a^2-45ab-14b^2=#
#7*2*a^2-7*7ab+2*2*ab-7*2*b^2=#
#(2a-7b)(7a+2b)=#
#(2x^3-7y^3)(7x^3+2y^3)#