How to factorize $14x^6 - 45x^3y^3 - 14y^6$ ?

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$14x^6 - 45x^3y^3 - 14y^6$

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Answer 1 · 2018-05-26T09:19:54

$(2x^3-7y^3)(7x^3+2y^3)$

By using substitution...

$a=x^3 and b=y^3$

$14x^6 - 45x^3y^3 - 14y^6=$
$14a^2-45ab-14b^2=$
$7*2*a^2-7*7ab+2*2*ab-7*2*b^2=$
$(2a-7b)(7a+2b)=$
$(2x^3-7y^3)(7x^3+2y^3)$