How do you write an equation of a line with point (5,-2), (7,1)?

1 Answer
May 26, 2018

y=3/2x-19/2

Explanation:

Find slope first: (y_2-y_1)/(x_2-x_1)
Let's have point 1 as (5,-2) and point 2 as (7,1)

points are (x,y) format, so in (5,-2), x_1 = 5 and y_1=-2 and in (7,1), x_2=7 and y_2=1

Therefore the solution will be like this:

Thus, slope m is: (1-(-2))/(7-5)
Simplifying, (1+2)/(7-5)=3/2

Let's use point-slope formula, y-y_1=m(x-x_1)
Adding in values, y-(-2)=3/2(x-5)

Now simplify and you get your equation. Make sure to isolate y

y+2=3/2x-15/2
y=3/2x-15/2-2\rArr3/2x-15/2-2
\rArry=3/2x-19/2