Use the inverse functions to find all solutions in the interval [0, 2π) 3cos^2(x) + 5cos(x) = 0?

1 Answer
May 25, 2018

pi/2 and (3pi)/2

Explanation:

We can factorise this equation to get:
cos(x)(3cos(x)+5)=0

cosx=0 or cosx=-5/3

x=cos^-1(0)=pi/2,2pi-pi/2;pi/2,(3pi)/2
or
x=cos^-1(-5/3)="undefined", abs(cos^-1(x))<=1

So, the only solutions are pi/2 and (3pi)/2