What is the standard form of y= (x+4)(2x-2)-(5x-2)^2?

1 Answer
May 25, 2018

y= -23x^2+26x-12

Explanation:

y=(x+4)(2x-2)-(5x-2)^2
y=x(2x-2)+4(2x-2)-[(5x-2)(5x-2)]
y=2x^2-2x+8x-8-[5x(5x-2)-2(5x-2)]
y=2x^2-2x+8x-8-[25x^2-20x+4]
y=2x^2-2x+8x-8-25x^2+20x-4
y=-23x^2+26x-12
Hope this helps!