Please solve q 56 ?

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2 Answers
P dilip_k
May 12, 2018

option (4) is acceptable

Explanation:

#a+b-c#

#=(sqrta+sqrtb)^2-(sqrtc)^2-2sqrt(ab)#

#=(sqrta+sqrtb+sqrtc)(sqrta+sqrtb-sqrtc)-2sqrt(ab)#

#=(sqrta+sqrtb+sqrtc)(sqrtc-sqrtc)-2sqrt(ab)#

#=(sqrta+sqrtb+sqrtc)xx0-2sqrt(ab)#

#=-2sqrt(ab)<0#

So #a+b-c<0=>a+b < c#
This means sum of the lengths of two sides is less than the third side . This is not possible for any triangle.
Hence formation of triangle is not possible i.e option (4) is acceptable

Abhishek K.
May 24, 2018

Option (4) is correct.

Explanation:

Given,

#rarrsqrt(a)+sqrt(b)=sqrtc#

#rarr(sqrt(a)+sqrt(b))^2=(sqrtc)^2#

#rarra+2sqrt(ab)+b=c#

#rarra+b-c=-2sqrt(ab)#

#rarra+b-c<0#

#rarra+b<##c#

So, no formation of triangle is possible.

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