How do you solve the system #4x=3y+31# and #y=2x+7# by substitution?

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Answer 1 · 2018-05-24T04:54:29

#(-26,-45)#

#4x= 3y+31#-------(1)
#y=2x+7#----------(2)

Put (2) in (1),

#4x= 3(2x+7)+31#

#4x= 6x+21+31#

#4x= 6x+52#

#2x=-52#

#x= -26#

put in equation (2)

#y=2(-26)+7#

#y=-52+7#

#y=-45#