How do you solve $x^{2} - 8 = 0$ $x^{2} - 8= 0$ ?

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How do you solve $x^{2} - 8 = 0$ $x^{2} - 8= 0$ ?

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Answer 1 · 2018-05-23T14:19:58

$x = \pm 2 \sqrt{2}$ $x=+-2sqrt2$

Explanation:

$isolate x^{2} by adding 8 to both sides$ $"isolate "x^2" by adding 8 to both sides"$

$x^{2} = 8$ $x^2=8$

$take the square root of both sides$ $color(blue)"take the square root of both sides"$

$\sqrt{x^{2}} = \pm \sqrt{8} \leftarrow note plus or minus$ $sqrt(x^2)=+-sqrt8larrcolor(blue)"note plus or minus"$

$\Rightarrow x = \pm 2 \sqrt{2}$ $rArrx=+-2sqrt2$

Answer 2 · 2018-05-23T14:22:23

$x = \pm 2 \sqrt{2}$ $x= +-2sqrt(2)$

Explanation:

$x^{2} - 8 = 0$ $x^{2} - 8= 0$

first add 8 to both sides:

$x^{2} = 8$ $x^{2}= 8$

now take the square root of both sides, remember you must use $\pm$ $+-$ the square root on the right side:

$\sqrt{x^{2}} = \pm \sqrt{8}$ $sqrt(x^{2})= +-sqrt(8)$

$x = \pm 2 \sqrt{2}$ $x= +-2sqrt(2)$

Answer 3 · 2018-05-23T14:57:16

$x = \pm 2 \sqrt{2}$ $x=+-2sqrt2$

Explanation:

$x^{2} - 8 = 0$ $color(blue)(x^2-8=0$

To, solve this, we need to isolate $x^{2}$ $x^2$ in one side of the equation. To do that, we can add or subtract the same number in both sides of the equation.

Add $8$ $8$ both sides

$\to x^{2} - 8 + 8 = 0 + 8$ $rarrx^2-8+color(red)(8)=0+color(red)(8)$

$\to x^{2} = 8$ $rarrx^2=8$

Now, take the square root of both sides,

$rarrsqrt(x^cancel2)=+-sqrt8$

$rarrx=+-sqrt8$

Now, take the prime factors of $8$

$rarrx=+-sqrt(underbrace(2*2)*2)$

$color(green)(rArrx=+-2sqrt2$

Remember that $+-$ means plus or minus

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How do you solve $x^{2} - 8 = 0$ $x^{2} - 8= 0$ ?

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How do you solve $x^{2} - 8 = 0$ $x^{2} - 8= 0$ ?