Find all angles a in the interval [0degrees, 360 degrees] such that sin^2a-sina =0?

1 Answer
Nghi N
May 23, 2018

0, 90^@, 180^@, 360^@

Explanation:

sin^2 a - sin a = 0
sin a(sin a - 1) = 0
Either factor should be zero -->
a. sin a = 0
Unit circle gives:
a = 0, a = 180^@, and a = 360^@
b. sin a - 1 = 0 --> sin a = 1
a = 90^2

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