X^2-3x-18/x+3? Simplify

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Answer 1 · 2018-05-20T00:43:32

#x+6#

#(x^2-3x-18)/(x+3)#

we need to factor first, the denominator will not factor but the numerator factors to:

#((x + 3) (x - 6))/(x+3)#

now cancel the factor #x+3# and we have the solution:

#x+6#

Answer 2 · 2018-05-20T00:45:58

#(x^2-3x-18)/(x+3)#=#x-6#

Firstly you need to factorize #x^2-3x-18#
#x^2-3x-18#=#(x+3)(x-6)#

Then you divide by #x+3#
#[(x+3)(x-6)]/(x+3)#=#x-6#