If I have a 254 mL bag at a temperature of 19.3 degrees C and I leave it in my car which has a temperature of 62.2 degrees C, what will the new volume of the bag be?

1 Answer
Al E.
May 18, 2018

Given,

#V_1 = 0.254"L"#

#T_1 = 292.45"K"#

#T_2 = 335.35"K"#

Let's derive the relationship between these two parameters from the ideal gas law,

#PV = nRT#

#=> V_1/T_1 = (nR)/P = V_2/T_2#

#=> V_1/T_1 = V_2/T_2#

Hence, the temperature of the bag at the higher temperature will be directly proportional to the increase in temperature, such that,

#=>V_2 = (V_1T_2)/T_1 approx 291"mL"#

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