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Answer 1 · 2018-05-18T22:20:07

Since you know the angles must add up to 180 you have a:

#90, 45, 45# triangle

okay, the pathogarean theorem says #a^2 + b^2 = c^2#

we know c = 9 and we also know a=b

so: #2a^2 = 9^2#

#a^2 = 9^2/2#

#a = sqrt(9^2/2)#

#a = 9/sqrt2#

#a = (9sqrt2)/2#

#A=1/2bh#

just turn the triangle so the short sides are the base and height.

#1/2*(9sqrt2)/2*(9sqrt2)/2 = 20.25#

Answer 2 · 2018-05-18T22:38:46

I tried this:

For problem 26 I got the following:

enter image source here

so the area will be:

#A=(9*4.5)/2=20.25"ft"^2#

For problem 27:
enter image source here

We know that the total perimeter is 44 units so the A (or B) bit will be:

#A=(44-20-4)/2=10#units:
and
#C=(20-4)/2=8#units

From Pythagoras:

#h=sqrt(10^2-8^2)=6# units

and the area of the trapezod:

#"Area"=1/2(20+4)*6=72# units squared