How do you rationalize the denominator and simplify #12/sqrt13#?

1 Answer
1s2s2p
May 18, 2018

#(12sqrt13)/13#

Explanation:

To rationalise the denominator for #a/sqrtb# you multiply by #sqrtb/sqrtb# since this turns the #sqrtb# on the bottom into a #b#, and is the same as multiply by #1#.

#12/sqrt13*sqrt13/sqrt13=(12sqrt(13))/13#

Since #12/13# cannot be simplified, we leave it as #(12sqrt13)/13#

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