A cone has a height of $15 c m$ $15 cm$ and its base has a radius of $9 c m$ $9 cm$ . If the cone is horizontally cut into two segments $6 c m$ $6 cm$ from the base, what would the surface area of the bottom segment be?

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A cone has a height of $15 c m$ $15 cm$ and its base has a radius of $9 c m$ $9 cm$ . If the cone is horizontally cut into two segments $6 c m$ $6 cm$ from the base, what would the surface area of the bottom segment be?

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Answer 1 · 2018-05-17T10:01:54

$\frac{324}{25} \cdot π$ $324/25*pi$

Explanation:

Since the change in base is constant, we can graph this as
the cone has a gradient of $\frac{5}{3}$ $5/3$ (It goes up 15 in the space of 9)
As y, or it's height is 6, then x, or its radius is $\frac{18}{5}$ $18/5$
The surface area would then be
${(\frac{18}{5})}^{2} \cdot π = \frac{324}{25} \cdot π$ $(18/5)^2*pi=324/25*pi$

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A cone has a height of $15 c m$ $15 cm$ and its base has a radius of $9 c m$ $9 cm$ . If the cone is horizontally cut into two segments $6 c m$ $6 cm$ from the base, what would the surface area of the bottom segment be?

1 Answer

Explanation:

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Science

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A cone has a height of 15cm15 cm and its base has a radius of 9cm9 cm. If the cone is horizontally cut into two segments 6cm6 cm from the base, what would the surface area of the bottom segment be?

1 Answer

Explanation:

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A cone has a height of $15 c m$ $15 cm$ and its base has a radius of $9 c m$ $9 cm$ . If the cone is horizontally cut into two segments $6 c m$ $6 cm$ from the base, what would the surface area of the bottom segment be?