Change into polar form #x^2+2y-1=0#?

1 Answer
1s2s2p
May 16, 2018

#r(rcos^2theta+2sintheta)=1#

Explanation:

First, we need the two equations to convert which are:
#x=rcostheta#
#y=rsintheta#

Putting these in gives us:
#(rcostheta)^2+2rsintheta-1=0#

#r^2cos^2theta+2rsintheta=1#

#r(rcos^2theta+2sintheta)=1#

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