If I have a 247 mL bag at a temperature of 20.9 degrees C, and I leave it in my car which has a temperature of 64.0 degrees C, what will the new volume of the bag be?

1 Answer
Reign
May 16, 2018

#color(red)(0.283L)#

Explanation:

Charle's Law #(V1)/(T1)=(V2)/(T2)#
#V#'s unit must be in liters (L) and Kelvin (K)=#C^@+273.15# for #T#

First, convert #mL->L#
#247cancel(mL)*(1L)/(1000cancel(mL))=0.247L#
Second, convert the temperature #C^@->K#
#20.9^@C+273.15=294.05#
#64.0^@C+273.15=337.15K#

#V_1=color(red)(0.247L)#
#T_1=color(red)(294.05K)#
#V_2=color(red)(?)#
#T_2=color(red)(337.15K)#

Now, rearrange the formula to get #V_2#
#V_2=V_1*(T_2)/(T_1)#
#V_2=color(red)(0.247L)*color(red)(337.15cancel(K))/(color(red)(294.05cancel(K))#
#V_2=color(red)(?)#

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