How do you evaluate #0= t ( 3.9- 4.9t )#?

1 Answer
Pretish
May 16, 2018

t=0 or/and t=#\frac{39}{49}#

Explanation:

You've already pretty much solved it.

Let the stuff outside the brackets equal 0 (since it's basically another bracket), giving you #t=0#

Then let the things inside the bracket equal 0, giving you #3.9-4.9t=0#

Rearrange for t in the second equation, which gives you #t=\frac{39}{49}#

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