What is #x + y=-1# graphed?

1 Answer
Kendra Francis · Tony B
May 15, 2018

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Explanation:

Subtract x from both sides. We get #y=-1-x#

Rearrange to receive the format #y=mx+b#. We get #y=-x-1#

Our m is equal to -1 and our b is equal to -1

We know our slope is negative (-1)

We know that -1 is our y-intercept (where is touches the y-axis) and for it to lie on the y-axis our x coordinate must be zero.

Thus, we can make the point (0, -1)

Plot this first on the graph. From here we know our slope (or m) is equal to -1 (which can also be written as #(-1)/1#.

Our slope is rise over run. We know that from point (0,-1) we must go down one (-1) and over to the right one (1). Similarly, we can go up one and over to the left one. Continue this pattern to receive enough points to draw an adequate line.

You may also pick any values (pick any integers) for #x# and plug it into the equation we have #y=-x-1# and solve for a y-value. this way we can make some points, plot them, and draw a line.

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