Solve the system of equations by finding the reduced row-echelon form of the augmented matrix for the system of equations? 9x-4y+z=-4 -x+2y-3z=20 4x+4y-z=43

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Answer 1 · 2018-05-15T18:15:19

#x = 3, y=7, and z = -3#

The augmented matrix is:

#[ (9,-4,1,|,-4), (-1,2,-3,|,20), (4,4,-1,|,43) ]#

Multiply row 1 by 8 and add it to row 1:

#[ (1,12,-23,|,156), (-1,2,-3,|,20), (4,4,-1,|,43) ]#

Add row 1 to row 2:

#[ (1,12,-23,|,156), (0,14,-26,|,176), (4,4,-1,|,43) ]#

Multiply row 1 by -4 and add it to row 3:

#[ (1,12,-23,|,156), (0,14,-26,|,176), (0,-44,91,|,-581) ]#

Multiply row 2 by #7/2# and add it to row 3:

#[ (1,12,-23,|,156), (0,14,-26,|,176), (0,5,0,|,35) ]#

Swap row 2 and row 3:

#[ (1,12,-23,|,156), (0,5,0,|,35), (0,14,-26,|,176) ]#

Divide row 2 by 5:

#[ (1,12,-23,|,156), (0,1,0,|,7), (0,14,-26,|,176) ]#

Multiply row 2 by -14 and add to row 3:

#[ (1,12,-23,|,156), (0,1,0,|,7), (0,0,-26,|,78) ]#

Divide row 2 by -26:

#[ (1,12,-23,|,156), (0,1,0,|,7), (0,0,1,|,-3) ]#

Multiply row 3 by 23 and add to row 1:

#[ (1,12,0,|,87), (0,1,0,|,7), (0,0,1,|,-3) ]#

Multiply row 2 by -12 and add to row 1:

#[ (1,0,0,|,3), (0,1,0,|,7), (0,0,1,|,-3) ]#