At a constant temperature of 18.0 degrees C, a 2.59 L container has a pressure of 266 kPa. If the gas pressure changes to 250. mmHg. what is the new volume?

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At a constant temperature of 18.0 degrees C, a 2.59 L container has a pressure of 266 kPa. If the gas pressure changes to 250. mmHg. what is the new volume?

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Answer 1 · 2018-05-13T15:14:34

$20.7$ $20.7$ L.

Explanation:

Use Boyle's law to solve this problem. The law is:

$P_{1} V_{1} = P_{2} V_{2}$ $P_1V_1=P_2V_2$

Next, you need to make sure all of the units are equal. Convert mmHg into kPa.

#250. mmHg * ((101.325 kPa)/(760 mmHg)) = 33.3 kPa

Now all you have to do is plug everything in and solve for $V_{2}$ $V_2$ .

$(266 k P a) (2.59 L) = (33.3 k P a) (V_{2})$ $(266 kPa)(2.59 L) = (33.3 kPa)(V_2)$
$V_{2} = \frac{(266 k P a) (2.59 L)}{33.3 k P a} = 20.7 L$ $V_2 = ((266 kPa)(2.59 L))/(33.3 kPa) = 20.7 L$

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At a constant temperature of 18.0 degrees C, a 2.59 L container has a pressure of 266 kPa. If the gas pressure changes to 250. mmHg. what is the new volume?

1 Answer

Explanation:

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