Limiting equilibrium means $m a = 0$ $ma=0$ In $F - f = m a$ $F-f=ma$ ?

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Answer 1 · 2018-05-12T19:58:52

yes

In the case of limiting friction the body moves with uniform

velocity

therefore the net force must be zero and that leads to zero acceleration.

the example is a body kept on an incline ...

the net force along the incline ( at an angle $θ$ $theta$ from the horizontal ) is

$m g . sin (θ)$ $mg. sin (theta)$ moving the body downward.

whereas the force of friction f is opposing this tendency

but f the frictional force has a limit which it can not exceed.

therefore $f = m . g . sin (θ)$ $f = m.g. sin (theta)$ or

$m g sin (θ) - f$ $mg sin (theta) -f$ = 0

therefore m.a =0

Limiting equilibrium means ma=0ma=0 In F−f=maF-f=ma ?